select fname, lname from employee |
select fname, lname from employee where dno = 4 |
Name and address of all employees:
SELECT fname, lname, address, dno
FROM employee
|
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You can see some resemblance between SQL and Relational Algebra....
Find project 'ProductX':
SELECT pnumber, pname
FROM project
WHERE pname = 'ProductX'
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Previously: find ssn of employees working on ProductX:
SELECT essn
FROM works_on, project
WHERE pname = 'ProductX'
AND pno = pnumber
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