Slideshow:
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Let: Sk = length of a search key (in bytes) Sp = length of a pointer (in bytes) |
Example:
BlockSize = 4096 bytes
Sk = 4 bytes (search key)
Sp = 8 bytes
Then:
4n + 8(n+1) ≤ 4096
12n + 8 ≤ 4096
12n ≤ 4088
n ≤ 340.666
===> n = 340 search keys in 1 block
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