- We know from
Set Theory that:
A ∩Set ( B ∪Set C ) = (A ∩Set B) ∪Set (A ∩Set C)
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- But, this
law does
not hold for
bags:
A = { x }
B = { x }
C = { x }
A ∩Bag ( B ∪Bag C ) = {x} ∩Bag ( {x} ∪Bag {x} )
= {x} ∩Bag {x,x}
= {x}
(A ∩Bag B) ∪Bag (A ∩Bag C) = ({x} ∩Bag {x}) ∪Bag ({x} ∩Bag {x})
= {x} ∪Bag {x}
= {x,x}
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