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Notes:
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Observations:
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U
Snon-persistent CSMA = ------ ...... (1)
B + I
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All we need to do now is to find U, B, and I :-)
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Notes:
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Ҏ[ I ≤ x ] = 1 - Ҏ[ I > x ]
= 1 - Ҏ[ no packet arrives in x sec ]
(Gx)0 Ҏ[ I ≤ x ] = 1 - ---- e-Gx 0! <=> Ҏ[ I ≤ x ] = 1 - e-Gx ...... (2) |
d Ҏ[ I ≤ x ]
fI(x) = ---------------
d x
d (1 - e-Gx)
<==> fI(x) = --------------
d x
<==> fI(x) = G e-Gx ...... (3)
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I = 0∫∞ x fI(x) dx (= the definition of expected value)
<=> I = 0∫∞ x G e-Gx dx
1 | x = ∞
<=> I = -x e-Gx - --- e-Gx |
G | x = 0
1
<=> I = ( 0 - 0 ) - ( 0 - --- )
G
1
<=> I = --- ..... (4)
G
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One down, two more to go....
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Notes:
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Notes to the figure above:
Ҏ[ transmission successful ] = Ҏ[ 0 arrivals within "vulnerable period" ]
= Ҏ[ 0 arrivals within τ sec ]
(Gτ)0 Ҏ[ transmission successful ] = ----- e-Gτ 0! <=> Ҏ[ transmission successful ] = e-Gτ ..... (5) |
U = T × Ҏ[ transmission successful ] + 0 × (1 - Ҏ[ transmission successful ])
= T × e-Gτ + 0 × (1 - e-Gτ)
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Two down, one more to go....